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authorXi Wang <xi.wang@gmail.com>2013-03-19 14:36:50 -0400
committerRuss Cox <rsc@swtch.com>2013-03-19 14:36:50 -0400
commit1bfec89b997c9544100128fec6e0b0c3757fdd11 (patch)
tree933faa410c29279f965b8218117ae91f8a7dc844 /src/cmd/upas/nfs/sx.c
parent8a2a5b8f2568a665f00741994c1247f0f7d3dffe (diff)
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rc: avoid undefined C
There are two bugs in pdec() on INT_MIN: * wrong output. `n = 1-n' should be `n = -1-n' when n is INT_MIN. * infinite loop. gcc optimizes `if(n>=0)' into `if(true)' because `-INT_MIN' (signed integer overflow) is undefined behavior in C, and gcc assumes the negation of a negative number must be positive. The resulting binary keeps printing '-' forever given INT_MIN. Try the simplified pdec.c below. $ gcc pdec.c $ ./a.out -2147483648 --214748364* $ gcc pdec.c -O2 $ ./a.out -2147483648 <infinite loop> $ gcc pdec.c -O2 -D__PATCH__ $ ./a.out -2147483648 -2147483648 === pdec.c === #include <stdio.h> #include <stdlib.h> #include <limits.h> #define io void void pchr(io *f, int c) { putchar(c); } void pdec(io *f, int n) { if(n<0){ #ifndef __PATCH__ n=-n; if(n>=0){ pchr(f, '-'); pdec(f, n); return; } /* n is two's complement minimum integer */ n = 1-n; #else if(n!=INT_MIN){ pchr(f, '-'); pdec(f, -n); return; } /* n is two's complement minimum integer */ n = -(INT_MIN+1); #endif pchr(f, '-'); pdec(f, n/10); pchr(f, n%10+'1'); return; } if(n>9) pdec(f, n/10); pchr(f, n%10+'0'); } int main(int argc, char **argv) { int n = atoi(argv[1]); pdec(NULL, n); putchar('\n'); } R=rsc CC=plan9port.codebot https://codereview.appspot.com/7241055
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