1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
|
#include <u.h>
#include <libc.h>
#include <draw.h>
#include <memdraw.h>
Memsubfont*
getmemdefont(void)
{
char *hdr, *p;
int n;
Fontchar *fc;
Memsubfont *f;
int ld;
Rectangle r;
Memdata *md;
Memimage *i;
/*
* make sure data is word-aligned. this is true with Plan 9 compilers
* but not in general. the byte order is right because the data is
* declared as char*, not u32int*.
*/
p = (char*)defontdata;
n = (uintptr)p & 3;
if(n != 0){
memmove(p+(4-n), p, sizeofdefont-n);
p += 4-n;
}
ld = atoi(p+0*12);
r.min.x = atoi(p+1*12);
r.min.y = atoi(p+2*12);
r.max.x = atoi(p+3*12);
r.max.y = atoi(p+4*12);
md = mallocz(sizeof(Memdata), 1);
if(md == nil)
return nil;
p += 5*12;
md->base = nil; /* so freememimage doesn't free p */
md->bdata = (uchar*)p; /* ick */
md->ref = 1;
md->allocd = 1; /* so freememimage does free md */
i = allocmemimaged(r, drawld2chan[ld], md, nil);
if(i == nil){
free(md);
return nil;
}
hdr = p+Dy(r)*i->width*sizeof(u32int);
n = atoi(hdr);
p = hdr+3*12;
fc = malloc(sizeof(Fontchar)*(n+1));
if(fc == 0){
freememimage(i);
return 0;
}
_unpackinfo(fc, (uchar*)p, n);
f = allocmemsubfont("*default*", n, atoi(hdr+12), atoi(hdr+24), fc, i);
if(f == 0){
freememimage(i);
free(fc);
return 0;
}
return f;
}
|